Aspire Faculty ID #16207 · Topic: NIMCET 2011 · Just now
NIMCET 2011

If $ |\vec{a}\times \vec{b}| = |\vec{a}\cdot \vec{b}| $, then angle $\theta$ between $\vec{a},\vec{b}$ is:

Solution

$ |\vec{a}\times \vec{b}| = ab\sin\theta $ $ |\vec{a}\cdot \vec{b}| = ab|\cos\theta| $ Equation: $ \sin\theta = |\cos\theta| $ Thus: $ \tan\theta = 1 $ In first quadrant: $ \theta = \pi/4 $

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