Aspire Faculty ID #16208 · Topic: NIMCET 2011 · Just now
NIMCET 2011

$ABCD$ is a parallelogram with diagonals $AC$ and $BD$. Compute $ \overrightarrow{AC} - \overrightarrow{BD} $.

Solution

In a parallelogram: $ \overrightarrow{AC} = \vec{a} + \vec{b} $ $ \overrightarrow{BD} = \vec{b} - \vec{a} $ So, $ \overrightarrow{AC} - \overrightarrow{BD} = (\vec{a}+\vec{b}) - (\vec{b}-\vec{a}) = 2\vec{a} = 2\overrightarrow{AB} $

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