Aspire Faculty ID #16200 · Topic: NIMCET 2011 · Just now
NIMCET 2011

Eccentricity of ellipse $ 9x^{2} + 5y^{2} - 30y = 0 $

Solution

Complete square: $ 5(y^{2} - 6y) = 5[(y-3)^{2} - 9] $ Thus: $ 9x^{2} + 5(y-3)^{2} = 45 $ Divide by 45: $ \frac{x^{2}}{5} + \frac{(y-3)^{2}}{9} = 1 $ Major axis along $y$ $ a^{2} = 9,\ b^{2} = 5 $ Eccentricity: $ e = \sqrt{1 - \frac{b^{2}}{a^{2}}} = \sqrt{1 - \frac{5}{9}} = \frac{2}{3} $

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