Aspire Faculty ID #16199 · Topic: NIMCET 2011 · Just now
NIMCET 2011

Vertex of parabola $ y^{2} - 8y + 19 = 0 $

Solution

$ y^{2} - 8y + 16 = -3 $ $ (y - 4)^{2} = -3 $ Axis horizontal, vertex is $(h,k) = (1,4)$

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