Aspire Faculty ID #16315 · Topic: NIMCET 2010 · Just now
NIMCET 2010

$\int \log_{10} x , dx$ is

Solution

Use change of base: $\log_{10} x = \dfrac{\ln x}{\ln 10}$ $\int \log_{10} x , dx = \dfrac{1}{\ln 10} \int x(\ln x)' dx = \dfrac{1}{\ln 10} (x\ln x - x)$ Rewrite: $= \log 10 \cdot x \log e\left(\frac{x}{e}\right) + c$

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