Aspire Faculty ID #16204 · Topic: NIMCET 2011 · Just now
NIMCET 2011

$ \text{The sum of } 11^{2} + 12^{2} + \cdots + 30^{2} \text{ is} $

Solution

$ \sum_{k=11}^{30} k^{2} = \frac{30\cdot 31 \cdot 61}{6} - \frac{10\cdot 11 \cdot 21}{6} = 9455 - 1385 = 8070 $

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